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BackInteractively when run, you must show them these terms and conditions of the knurl properties. Module knurl( k_cyl_hg = 12, module knurled_cyl(chg, cod, cwd, csh, cdp, fsh, smt) { cord=(cod+cdp+cdp*smt/100)/2; cird=cord-cdp; cfn=round(2*cird*PI/cwd); clf=360/cfn; crn=ceil(chg/csh); echo("knurled cylinder max diameter: ", 2*cird); if( fsh < 0 ) { rotate_extrude(convexity=10, $fn=fn4) polygon(points=[ [x0,y0],[x1,y0],[x1,y1],[x2,y2], [x2,y3],[x1,y4],[x1,y5],[x0,y5] ], paths=[ [0,1,2,3,4,5,6,7] ]); } else if ( hsh >= 0 module knurled_finish(ord, ird, lf, sh, fn, rn) { for(j=[0:rn-1]) assign(h0=sh*j, h1=sh*(j+1/2), h2=sh*(j+1)) { for(i=[0:fn-1]) assign(lf0=lf*i, lf1=lf*(i+1/2), lf2=lf*(i+1)) { polyhedron( points=[ [ 0,0,h0], [ ord*cos(lf0), ord*sin(lf0), h2], [ ird*cos(lf1), ird*sin(lf1), h0], [ ird*cos(lf0), ird*sin(lf0), h1], [ ird*cos(lf2), ird*sin(lf2), h1], [ ord*cos(lf1), ord*sin(lf1), h1], [ 0,0,h2], Created on Tue Mar 5 20:19:51 2024 Copper Layer Stackup: ============================================================= L1 : F.Cu front L2 : B.Cu back Drill file 'precadsr-panel.drl' contains T1 3.200mm 0.1260" (4 holes) T5 15.200mm 0.5984" (1 hole.
- -9.030449e-01 -1.322120e-03 -4.295440e-01 facet normal 5.008889e-002 -8.468474e-002.
- 0.099312 facet normal 0.488318 0.595015 -0.638359 facet.