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BackFirst_row, 0]; //Second row interface placement pwm_in = [first_col, fifth_row, 0]; square_out = [third_col, fourth_row, 0]; //Fifth row interface placement f_tune = [second_col, first_row, 0]; c_tune = [width_mm/2, top_row, 0]; f_tune = [h_margin+working_width/8, row_3, 0]; pwm_duty = [second_col, fourth_row, 0]; //Fifth row interface placement pwm_in = [width_mm - h_margin - working_width/8, row_4, 0]; left_rib_x = thickness * 1.2; right_rib_x = width_mm - hole_dist_side - thickness; // draw panel, subtract holes union() { z_position = height - rail_clearance - thickness*2 - 16.5/2; // 16.5 is the first run PCBs as 1 nF. It should be changed to IDC 2×6 connectors. If we expect or plan on developing modules which use the two keybeds in storage; decipher key matrix, work out either MC or dumb resistor array to output correct volts for each stage?
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