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By 3.16 mm. (8.89 mm vs (10.54+1.52) mm if I'm reading it right. Latest commits for file Images/IMG_6770.JPG Binary files /dev/null and b/Panels/luther_triangle_10hp_rib_space_fixes.stl differ synth_tools/Synth_Manuals/The MIDI Manufacturers Association - 1995 - MIDI 1.0 Detailed Specification.pdf elseif (strpos($article["link"], "satwcomic.com/") !== FALSE) { $xpath = $this->get_xpath_dealie($article['link']); $article['content'] = $this->get_img_tags($xpath, "//img[@class='ksc' and contains(@src, 'comics')]", $article); } */ // // Decorations // // indentations // // top horizontal rib h_wall(h=1.6, l=right_rib_x); // middle horizontal rib h_wall(h=4, l=right_rib_x); } module knurled_finish(ord, ird, lf, sh, fn, rn) { for(j=[0:rn-1]) assign(h0=sh*j, h1=sh*(j+1/2), h2=sh*(j+1)) { for(i=[0:fn-1]) assign(lf0=lf*i, lf1=lf*(i+1/2), lf2=lf*(i+1)) { polyhedron( points=[ [ 0,0,h0], [ ord*cos(lf0), ord*sin(lf0), h0], [ ird*cos(lf1), ird*sin(lf1), h2], [ ird*cos(lf1), ird*sin(lf1), h0], [ ird*cos(lf0), ird*sin(lf0), h1], [ ird*cos(lf2), ird*sin(lf2), h1], [ ord*cos(lf0), ord*sin(lf0), h0], [ ird*cos(lf0), ird*sin(lf0), h1], [ ird*cos(lf2), ird*sin(lf2), h1], [ ird*cos(lf2), ird*sin(lf2), h1], [ ird*cos(lf2), ird*sin(lf2), h1], [ ord*cos(lf1), ord*sin(lf1), h1], [ ird*cos(lf2), ird*sin(lf2), h1], [ ird*cos(lf2), ird*sin(lf2), h1], [ 0,0,h2], Created on Tue Mar 5 20:19:51 2024 L1 : F.Cu front L2 : B.Cu back Drill file 'precadsr-panel.drl' contains T1 3.200mm 0.1260" (4 holes) (with 4 slots T2 5.000mm 0.1969" (1 hole) Total plated holes.

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